Answer
$W= 25\sqrt 2$ $J$
Work Step by Step
$W= |\textbf{F}||\textbf{d}|cos(\theta) = (5)(10)cos(45^\circ)) = 50 \times \frac{\sqrt 2}{2} = 25\sqrt 2$ $J$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 11 - Vectors and Vector-Valued Functions - 11.3 Dot Products - 11.3 Exercises - Page 789: 39
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