Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - Review Exercises - Page 53: 49

Answer

$$0$$

Work Step by Step

$$\eqalign{ & {\sin ^{ - 1}}x + {\sin ^{ - 1}}\left( { - x} \right) \cr & {\text{Recall that si}}{{\text{n}}^{ - 1}}\theta {\text{ is an odd function, then }}{\sin ^{ - 1}}\left( { - x} \right) = - {\sin ^{ - 1}}x \cr & {\text{then,}} \cr & {\sin ^{ - 1}}x - {\sin ^{ - 1}}x \cr & 0 \cr} $$
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