Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises: 95

Answer

No definite parity - neither even nor odd.

Work Step by Step

We have that $E(-x)=E(x)$ and $O(-x)=-O(x)$. Let $\Phi=E+O$. Then $$\Phi(-x)=E(-x)+O(-x)=E(x)-O(x)$$ which is different than both $\Phi(x)$ and $-\Phi(x)$ so this function is neither even nor odd.
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