Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises: 62

Answer

$\frac{f(x)-f(a)}{x-a}=(x+a)(x^2+a^2)$

Work Step by Step

$f(x) = x^4$ $\frac{f(x)-f(a)}{x-a}=\frac{x^4-a^4}{x-a} = \frac{(x^2-a^2)(x^2+a^2)}{(x-a)} =\frac{(x-a)(x+a)(x^2+a^2)}{(x-a)}=\frac{(x+a)(x^2+a^2)}{1}=(x+a)(x^2+a^2)$
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