Answer
$(a)\frac{df}{dx}=-66x^{-4}-66x^2$
$ \int\frac{df}{dx}dx= 22x^{-3}-22{x^3}+C$
Work Step by Step
$f(x)=22x^{-3}-22x^3$
$(a)\frac{df}{dx}=-66x^{-4}-66x^2$
(b)
$ \int\frac{df}{dx}dx= \int (-66x^{-4}-66x^2)dx$
$ \int\frac{df}{dx}dx= (-66)[\int (x^{-4}+x^2)dx]$
$ \int\frac{df}{dx}dx= (-66)[\int x^{-4}dx+\int x^2dx]$
$ \int\frac{df}{dx}dx= (-66)[(\frac{x^{-3}}{-3})+\frac{x^3}{3}]$
$ \int\frac{df}{dx}dx= 22x^{-3}-22{x^3}+C$
