## Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

$m(4.5)\approx3.688$ $m(-2)=1.25$
This is the same concept as exercise 11, but different numbers. If $m(t)=\frac{3}{8}t+2$, find $m(4.5)$ and $m(-2)$. $m(4.5)$: $m(t)=\frac{3}{8}t+2$ (Original function $m(4.5)=\frac{3}{8}(4.5)+2$ (Substitution) $m(4.5)=\frac{3}{8}(\frac{9}{2})+2$ (Changing into a fraction) $m(4.5)=\frac{27}{16}+2=\frac{27+32}{16}=\frac{59}{16}$ $m(4.5)\approx3.688$ $m(-2)$: $m(t)=\frac{3}{8}t+2$ $m(-2)=\frac{3}{8}*-2+2$ $m(-2)=-\frac{3}{4}+2$ $m(-2)=2-\frac{3}{4}=\frac{5}{4}=1.25$