## Calculus 8th Edition

$L = \int ^{1}_{-1} \sqrt{1+4y^2e^{2y^{2}}}dy$
$y^{2} = \ln x$ then $x = e^{y^{2}}$ and $dx/dy = 2ye^{y^{2}}$ and $1+(dx/dy)^2 = 1+4y^2e^{2y^{2}}$ $L = \int ^{1}_{-1} \sqrt{1+4y^2e^{2y^{2}}}dy$