Answer
$\tan x-x+C$
Work Step by Step
$\int\tan^2 x\ dx$
Use the identity $\sec^2 x=1+\tan^2 x$ to rewrite $\tan^2 x$ as $\sec^2-1$:
$=\int(\sec^2 x-1)dx$
$=\boxed{\tan x-x+C}$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 7 - Techniques of Integration - 7.2 Trigonometric Integrals - 7.2 Exercises - Page 524: 23
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