Answer
$(\sec^2\theta)e^{\tan \theta}$
Work Step by Step
$\frac{d}{d\theta}e^{\tan\theta}$
$=e^{\tan\theta}\frac{d}{d\theta}\tan\theta$
$=(\sec^2\theta)e^{\tan \theta}$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.2 Exponential Functions and Their Derivatives - 6.2 Exercises - Page 418: 37
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