Answer
$\int_0^\pi \sin(x) dx=2$
Work Step by Step
$$\begin{align*}
\lim_{n \to \infty}\sum_{i=1}^{n}\sin(x_i)\Delta x&=\int_0^\pi \sin(x) dx\\
&=[-\cos(x)]_0^\pi\\
&=-\cos(\pi)-(-\cos(0))\\
&=1+1\\
&=2
\end{align*}$$
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