Chapter 4 - Integrals - 4.3 The Fundamental Theorem of Calculus - 4.3 Exercises - Page 330: 84

$$ \int_{1}^{3} \frac{y^{3}-2 y^{2}-y}{y^{2}} d y=-\ln \left(3\right) $$

$$ \begin{aligned} \int_{1}^{3} \frac{y^{3}-2 y^{2}-y}{y^{2}} d y&= \int _1^3 (y-2-\frac{1}{y})dy\\ &=\int _1^3ydy-\int _1^32dy-\int _1^3\frac{1}{y}dy\\ &= \frac{1}{2}y^{2}|_{1}^{3} -2y|_{1}^{3}-ln(y)|_{1}^{3}\\ &=4-4-\ln \left(3\right)\\ &=-\ln \left(3\right) \end{aligned} $$