Answer
See proof
Work Step by Step
Differentiate both sides of the given equation $f(g(x))=x$:
$$g'(x)f'(g(x))=1$$
$$g'(x)(1+[f(g(x))]^{2}=1$$
$$g'(x)(1+x^{2})=1$$
$$g'(x)=\frac{1}{(1+x^{2})}$$
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