Answer
$g'(t) = \frac{-1}{2}t^{\frac{-3}{2}}$
Domain: t $\gt$ 0
Work Step by Step
$g(t) = \frac{1}{\sqrt t} = t^{-1/2}$
$g'(t) = (-1/2)t^{(-1/2) - 1}$
$g'(t) = \frac{-1}{2}t^{\frac{-3}{2}}$
The domain is t $\gt$ 0 because for any negative t value or if t = 0, then g'(t) would be undefined