Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.2 The Derivative as a Function - 2.2 Exercises: 24

Answer

$g'(t) = \frac{-1}{2}t^{\frac{-3}{2}}$ Domain: t $\gt$ 0

Work Step by Step

$g(t) = \frac{1}{\sqrt t} = t^{-1/2}$ $g'(t) = (-1/2)t^{(-1/2) - 1}$ $g'(t) = \frac{-1}{2}t^{\frac{-3}{2}}$ The domain is t $\gt$ 0 because for any negative t value or if t = 0, then g'(t) would be undefined
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.