Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - Review - True-False Quiz: 1

Answer

False

Work Step by Step

Consider $x=f(t)=(t-1)^{3}$ and $y=g(t)=(t-1)^{2}$ Thus $g'(t)=2(t-1)$ Now put $t=1$ $g'(1)=2(1-1)=0$ which is not equal to $1$ as per the given statement , that is, $g'(1)\ne 1$ but it has vertical tangent at $t=1$ Hence , the statement is false.
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