## Calculus 8th Edition

See p.76, The Precise Definition of a Limit: ... $\displaystyle \lim_{x\rightarrow a}f(x)=L$ if for every number $\epsilon > 0$ there is a number $\delta > 0$ such that if $0 < |x-a| < \delta$ then $|f(x)-L| < \epsilon$. ---------- The statement matches the definition, with $\epsilon =1$, $a=0, L=6.$