Answer
$x=\pm 1$ or $x=\pm i$
Work Step by Step
We solve by factoring:
$x^{4}=1$
$x^{4}-1=0$
We use the fact that $a^2-b^2=(a+b)(a-b)$:
$(x^{2}-1)(x^{2}+1)=0$
$x^{2}-1=0$ or $x^{2}+1=0$
$x^2=1$ or $x^2=-1$
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