Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 8 - Mathematical Modeling With Differential Equations - 8.2 Separation Of Variables - Exercises Set 8.2 - Page 576: 33

Answer

$230.26$ days

Work Step by Step

Fly Population Growth Analysis Step 1 To solve this problem, first use Formula (13) to set up the equation for the number of flies in the container after $t$ days, then solve the equation $y(t) = 10000$. Step 2 Initially, there are 100 flies in the container, and the growth rate is 0.02. Since the growth is exponential, by Formula (13): \[ y(t) = 100e^{0.02t}, \] where $y(t)$ denotes the number of flies in the container after $t$ days. Step 3 Next, solve the equation $y(t) = 10000$: \[ 100e^{0.02t} = 10000. \] Divide by 100: \[ e^{0.02t} = 100. \] Take the natural logarithm: \[ 0.02t = \ln 100. \] Simplify: \[ t = \frac{\ln 100}{0.02} \approx 230.26. \] Step 4 Finally, we have calculated that the container will reach capacity after approximately 230 days. Result The container will reach capacity after approximately 230.26 days.
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