Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.7 Rectilinear Motion Revisited Using Integration - Exercises Set 4.7 - Page 331: 40

Answer

(b) 154.3mi/h (a) 7.071s

Work Step by Step

\[ \begin{array}{l} s(t)=s_{0}+v_{0} t -\frac{g}{2} t^{2}\\ v(t)=v_{0}-g t \end{array} \] $g=32 \mathrm{ft} / \mathrm{s}^{2}$ Using Formula (15) and Formula (16) from the book: (a) $0=s(t)=800-16 t^{2}$ $\Rightarrow 7.071\mathrm{s}=\sqrt{\frac{-800}{-16}}=t$ $s_{0}=800$, $v_{0}=0$ and $s(t)=0$ (b) $-32 t=v(t)$ Velocity at $t=7.071$: $v(50)= 7.071 \cdot (-32)=-226.27 \mathrm{ft} / \mathrm{s}=154.3 \mathrm{mi} / \mathrm{h}$
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