Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Section 10.5 - Finding Factors of Special Products - Exercise - Page 354: 33

Answer

$(2m-3)(2m+3)$

Work Step by Step

This is a difference between two squares, and hence $$ 4m^2-9=(2m-3)(2m+3) .$$ One can check as follows $$ (2m-3)(2m+3)=4m^2-6m+6m-9=4m^2-9 .$$
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