Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Unit 1B Review: 7

Answer

$\frac{4}{15}$

Work Step by Step

Factor each part then cancel common factors to obtain: $\require{cancel} =\frac{5}{4(3)} \times \frac{4(4)}{5(5)} \\=\frac{\cancel{5}}{\cancel{4}(3)} \times \frac{4\cancel{(4)}}{5\cancel{(5)}} \\=\frac{1}{3}\times \frac{4}{5} \\=\frac{1(4)}{3(5)} \\=\frac{4}{15}$
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