Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 4 - Vector Spaces - 4.4 Exercises - Page 224: 8

Answer

The coordinate vector is; $[x]_{\beta}=\begin{bmatrix}{c_1}\\{c_2}\\c_{3}\end{bmatrix} = \begin{bmatrix}-2\\0\\5\end{bmatrix}$

Work Step by Step

Find the coordinate vector $[x]_{\beta}$ of $x$ relative to the given basis $\beta$ Basis matrix; $\beta = \begin{bmatrix}1&2&1\\{ 0}&{1}&-1\\3&8&2\end{bmatrix}$ and ${\bf{x}} = \begin{bmatrix}{ 3\\-5}\\4\end{bmatrix}$ Finding $[x]_{\beta}$ $\beta {\left[ x \right]_\beta } = x$ $\begin{bmatrix}1&2&1\\{ 0}&{1}&-1\\3&8&2\end{bmatrix}\begin{bmatrix}c_{1}\\c_{2}\\c_{3}\end{bmatrix}=\begin{bmatrix}3\\-5\\4\end{bmatrix}$ Forming augmented matrix and row reducing; $\begin{bmatrix}1&2&1&3\\{ 0}&{1}&-1&-5\\3&8&2&4\end{bmatrix}\sim\begin{bmatrix}1&0&0&-2\\0&1&0&0\\0&0&1&5\end{bmatrix}$ The coordinate vector is; $[x]_{\beta}=\begin{bmatrix}{c_1}\\{c_2}\\c_{3}\end{bmatrix} = \begin{bmatrix}-2\\0\\5\end{bmatrix}$
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