## Linear Algebra and Its Applications (5th Edition)

The general solution of the matrix is: 3 -2 4 0 0 0 0 0 0 0 0 0 In parametric form, this is expressed as: $x_{1}$ = $\frac{2}{3}x_{2}$ - $\frac{4}{3}x_{3}$ $x_{2}$ is free $x_{3}$ is free