Answer
The general solution of the matrix is:
3 -4 2 0
0 0 0 0
0 0 0 0
In parametric form, this is expressed as:
$x_{1}$ = $\frac{4}{3}x_{2}$ - $\frac{2}{3}x_{3}$
$x_{2}$ is free
$x_{3}$ is free
Work Step by Step
We begin with the original matrix.
3 -4 2 0
-9 12 -6 0
-6 8 -4 0
We divide the second row by -3, and the third row by -2.
3 -4 2 0
3 -4 2 0
3 -4 2 0
Rows two and three can be reduced to rows of zeroes, meaning that they are redundant and that the system has no unique solution and two free variables.
3 -4 2 0
0 0 0 0
0 0 0 0
