Answer
$(2w+5)(2w-1)$
Work Step by Step
$4w^{2}+8w-5$
Two factors of $ac=-20$, whose sum is $b=8$
are $10$ and $-2$.
Rewrite $8w$ as$ 10w-2w$ and factor in pairs.
$4w^{2}+8w-5$
$=4w^{2}+10w-2w-5\qquad$...factor from each group if possible.
$=2w(2w+5)-(2w+5)\qquad$...factor out the common binomial factor,$2w+5$.
$=(2w+5)(2w-1)$
