Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.7 - Negative Exponents and Scientific Notation - Exercise Set: 8

Answer

$-\dfrac{1}{49}$

Work Step by Step

Using $x^{-a}=\dfrac{1}{x^a}$the given expression, $ -7^{-2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{-1}{7^2} \\\\= \dfrac{-1}{49} \\\\= -\dfrac{1}{49} .\end{array}
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