Answer
$x(x+1)$ or $x^2+x$
Work Step by Step
RECALL:
$\log_b{x}+\log_b{y} =\log_b{(xy)}$
Use the rule above to obtain:
$\log_3{[x(x+1)]}=2$
Thus, the missing expression in the given statement is:
$x(x+1)$ or, when multiplied, $x^2+x$