Answer
$0$
Work Step by Step
RECALL:
$\ln{1}=0$ (refer to page 698 of the textbook)
Thus, the given expression is equal to 0.
An alternate solution would be:
RECALL:
$\ln{x} = y \longrightarrow e^y=x$
Thus,
$\ln{1} =y\longrightarrow e^y=1$
Note that $e^0=1$.
Replace $1$ with $e^0$ to obtain:
$e^y = e^0$
Use the rule "If $a^m=a^n$, then $m=n$" to obtain:
$y=0$
Therefore $\ln{1}=y=0$
