Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Review Exercises: 24

Answer

$49^{\frac{1}{2}}=7$

Work Step by Step

RECALL: $y=\log_b{x} \longrightarrow b^y=x$ Use the rule above with $y=\frac{1}{2}$, $b=49$, and $x=7$ to obtain: $49^{\frac{1}{2}}=7$
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