Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Mid-Chapter Check Point - Page 716: 34

Answer

$=\ln \left [ \frac{\sqrt x}{ y^3(z-2)} \right]$.

Work Step by Step

The given expression is $=\frac{1}{2}\ln x-3\ln y-\ln (z-2)$ Use power rule. $=\ln x^{\frac{1}{2}}-\ln y^3-\ln (z-2)$ $=\ln \sqrt x-[\ln y^3+\ln (z-2)]$ Use product rule. $=\ln \sqrt x-\ln [y^3(z-2)]$ Use quotient rule. $=\ln \left [ \frac{\sqrt x}{ y^3(z-2)} \right]$.
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