Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set: 5

Answer

$-2$

Work Step by Step

RECALL: $a^{\frac{1}{n}}=\sqrt[n]{a}$ $\sqrt [n] {a^{n}}=a$ With $n=4$, use the rules above to obtain: $-16^{\frac{1}{4}} \\=-(16^{\frac{1}{4}}) \\=-\sqrt[4]{16} \\=-\sqrt[4] {2^{4}} \\=-2$
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