Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.4 - Factoring Trinomials - Exercise Set - Page 362: 86

Answer

$(x^3+5)(2x^3+3)$.

Work Step by Step

The given expression is $=2x^6+13x^3+15$ We can write $=2(x^3)^2+13x^3+15$ Substitute $x^3=u$. $=2(u)^2+13u+15$ Simplify. $=2u^2+13u+15$ Rewrite $13u$ as $10u+3u$. $=2u^2+10u+3u+15$ Factor. $=2u(u+5)+3(u+5)$ $=(u+5)(2u+3)$. Substitute back $u=x^3$. $=(x^3+5)(2x^3+3)$.
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