Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.3 - Greatest Common Factors and Factoring by Grouping - Exercise Set: 41

Answer

$(3x-1)(4x^2+1)$

Work Step by Step

The given expression can be written as: $4x^2(3x-1)+(3x-1)$ The $GCF$ for the two terms is a binomial, $(3x-1)$. Even though it is a binomial, we can factor it out just like we would factor out a number or a variable. Thus, we factor out the binomial to obtain: $=(3x-1)(4x^2+1)$
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