Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Test - Page 101: 28

Answer

$15$ years.

Work Step by Step

Let the number of crossing $=x$. Toll to a bridge costs $=\$8$. Total costs for crossing $x$ times $=8t$. Monthly discount pass $=\$45$. With discount the toll is $\$5$. Total costs for crossing $x$ times $=45+5t$. Equate both total costs to find the number of crossing for which both are same. $\Rightarrow 8t=45+5t$ Subtract $5t$ from both sides. $\Rightarrow 8t-5t=45+5t-5t$ Simplify. $\Rightarrow 3t=45$ Divide both sides by $3$. $\Rightarrow \frac{3t}{3}=\frac{45}{3}$ Simplify. $\Rightarrow t=15$ Hence, after $15$ years both total costs are equal.
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