Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.1 - Algebraic Expressions, Real Numbers, and Interval Notation - Exercise Set: 127

Answer

$8+2 \cdot (4-3)$

Work Step by Step

Note that $10=8+2$. The last two numbers from the left can be grouped together to obtain: $=8 + 2\cdot (4 - 3) \\=8+2(1) \\= 8+2 \\= 10$
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