Chapter 6 - Logarithmic Functions - 6.6 Solving Logarithmic Equations - 6.6 Exercises - Page 534: 27

$L(I)=110 $ dB

$I=10^{-1}$ watts per second Putting in the equation: $L(I)=10\log \frac{I}{10^{-12}} $ $L(I)=10\log \frac{10^{-1}}{10^{-12}}$ $L(I)=10\log( 10^{-1}\times10^{12})$ $L(I)=10\log( 10^{-1+12})$ $L(I)=10\log( 10^{11})$ $L(I)=10\times11\log 10$ $L(I)=110\log 10$ $L(I)=110$ dB