Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.5 Solving Exponential Equations - 6.5 Exercises - Page 527: 42

Answer

$x = ±2$

Work Step by Step

$10^{x^{2}-5} = 0.10$ $10^{x^{2}-5} = 10^{-1} $ $x^{2} - 5 = -1$ $x^{2} = -1 + 5$ $x^{2} = 4$ $x = ±\sqrt 4$ $x = ±2$
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