Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 2 - Systems of Linear Equations and Inequalities - Chapter Review Exercises - Page 211: 41

Answer

$4\le x \le10$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given inequality, $ |x-7|\le3 ,$ use the definition of absolute value inequality. Then use the properties of inequality to isolate the variable. Finally, graph the solution set. In the graph, a hollowed dot is used for $\lt$ or $\gt.$ A solid dot is used for $\le$ or $\ge.$ $\bf{\text{Solution Details:}}$ Since for any $c\gt0$, $|x|\lt c$ implies $-c\lt x\lt c$ (or $|x|\le c$ implies $-c\le x\le c$), the inequality above is equivalent to \begin{array}{l}\require{cancel} -3\le x-7 \le3 .\end{array} Using the properties of inequality, the inequality above is equivalent to \begin{array}{l}\require{cancel} -3\le x-7 \le3 \\\\ -3+7\le x-7+7 \le3+7 \\\\ 4\le x \le10 .\end{array} Hence, the solution set is $ 4\le x \le10 .$
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