Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 2 - Systems of Linear Equations and Inequalities - 2.1 Systems of Linear Equations - 2.1 Exercises - Page 142: 42

Answer

See sample answer below.

Work Step by Step

We need two lines that pass through ($-5,-3$). Take one line with slope 1, m=1 $y=1\cdot x+b\quad $ ... substitute x and y, solve for b $-3=-5+b$ $-3+5=b$ $2=b\quad $... so our first line is $y=x+2$ Take one line with slope $2$, m=$2$ $y=2\cdot x+b\quad $ ... substitute x and y, solve for b $-3=2(-5)+b$ $-3+10=b$ $7=b\quad $... so our second line is $y=2x+7$ We have the y-intercepts for each line, and each passes through $(-5,-3$) ($-5,-3$) is the solution to $\left\{\begin{array}{l} y=x-2\\ y=2x+1 \end{array}\right.$
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