Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 598: 1

Answer

$(f\cdot g)(x)=2x^2-3x$

Work Step by Step

Since $(f\cdot g)(x) = f(x)\cdot g(x)$, then, \begin{array}{l} (f\cdot g)(x)=x(2x-3)\\\\ (f\cdot g)(x)=2x^2-3x .\end{array}
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