Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Graphing Calculator Explorations - Page 590: 3

Answer

23.16 years or 23 years and 2 months

Work Step by Step

10000 dollars initial amount 40000 dollars desired amount 6% interest Compounds monthly $A=40000$ $P=10000$ $r=.06$ $n=12$ $A=P(1+(r/n))^{n*t}$ $40000=10000*(1+(.06/12))^{12*t}$ $40000/10000=10000*(1+(.06/12))^{12*t}/10000$ $4=(1+(.06/12))^{12*t}$ $4=(1+(.005))^{12*t}$ $4=1.005^{12*t}$ $ln 4=ln (1.005^{12*t)}$ $ln 4= 12*t*ln 1.005$ $ln 4/12*ln 1.005 = 12*t*ln1.005/12*ln 1.005$ $1.38629/12*.0049875 =t$ $1.38629/.05985=t$ $23.162 =t$ 23.16 years or 23 years and 2 months
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