Answer
Please see below as to why $log_2 (1/x) = - log_2 x$.
Work Step by Step
$log_2 (1/x)$
$log_2 x^{-1}$
By the power of exponents, $log_2 x^{-1} = -1 *log _2 x$
$-1 *log _2 x= -log_2 x$
$log_2 (1/x) = - log_2 x$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Section 9.6 - Properties of Logarithms - Vocabulary, Readiness & Video Check - Page 578: 9
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