Answer
$-5, 5$
Work Step by Step
$x-y=10$
$x*y=z$
$x-y=10$
$x-y+y=10+y$
$x=10+y$
$x*y=z$
$(10+y)*y=z$
$10y+y^2=z$
$y^2+10y=z$
$a=1$, $b=10$
Vertex is at $y=-b/2a$
$y=-10/2*1$
$y=-10/2$
$y=-5$
$x-y=10$
$x-(-5)=10$
$x+5=10$
$x+5-5=10-5$
$x=5$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 8 - Section 8.6 - Further Graphing of Quadratic Functions - Exercise Set - Page 527: 61
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