Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.5 - Quadratic Functions and Their Graphs - Vocabulary, Readiness & Video Check: 12

Answer

$(0, -1)$

Work Step by Step

The vertex-form of a quadratic function is $y=a(x-h)^{2}+k$ where the vertex is the opposite of $h$ and $k$, or $(h, k)$. Given the function from the problem, $h(x)=x^{2}-1$, written in vertex form this function looks like $f(x)=1(x-0)^{2}+(-1)$. Therefore the vertex is at $(0, -1)$.
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