Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Test - Page 471: 29

Answer

$7+24i$

Work Step by Step

Using $(a+b)^2=a^2+2ab+b^2$ and $i^2=-1$, the given expression, $ (4+3i)^2 ,$ simplifies to \begin{array}{l}\require{cancel} (4)^2+2(4)(3i)+(3i)^2 \\\\= 16+24i+9i^2 \\\\= 16+24i+9(-1) \\\\= 16+24i-9 \\\\= 7+24i .\end{array}
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