Answer
$\text{approximately } 1,191 \text{ } ft$
Work Step by Step
Let $x$ be the distance from base of tower. Using $a^2+b^2=c^2$ or the Pythagorean Theorem, the conditions of the problem translate to
\begin{array}{l}\require{cancel}
x^2+2063^2=2382^2
.\end{array}
Using the properties of equality, the equation above is equivalent to
\begin{array}{l}\require{cancel}
x^2=2382^2-2063^2
\\
x^2=5673924-4255969
\\
x^2=1417955
.\end{array}
Taking the square root of both sides, the equation above is equivalent to
\begin{array}{l}\require{cancel}
x=\sqrt{1417955}
\\
x\approx1191
.\end{array}
Hence, the distance from base of tower, $x$ is $
\text{approximately } 1,191 \text{ } ft
.$