Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.4 - Adding, Subtracting, and Multiplying Radical Expressions - Vocabulary, Readiness & Video Check: 5

Answer

$6\sqrt3$

Work Step by Step

Since these are like terms, they can be added. Think of radicals as variable terms - it's a helpful trick when deciding what you can add and what you cannot. For example: $2\sqrt3$ $+$ $4\sqrt3$ can be compared to: $2x+4x$... you know these can be added: $6x$ Therefore: $2\sqrt3$ $+$ $4\sqrt3$ $=6\sqrt3$
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