Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Vocabulary, Readiness & Video Check - Page 416: 12

Answer

$8y^{10}$

Work Step by Step

$(8y^{10){2}} = 8^{2} \times y^{20} =64y^{20}$ or... $\sqrt 64 = 8, and \sqrt y^{20} = y^{10} = 8y^{10}$
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