Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 326: 105

Answer

the first equation results to two solutions while the second equation results to three solutions

Work Step by Step

Solving $2(x-3)(x-1)=0$ differs from solving $2x(x-3)(x-1)=0$ because the first equation results to two solutions while the second equation results to three solutions. When $2$ is divided in both sides of the given equations, the first equation results to $2$ factors only, while the second equation results to $3$ factors.
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