Chapter 4 - Section 4.1 - Solving Systems of Linear Equations in Two Variables - Exercise Set - Page 213: 89

Answers will vary.

Here, we simply need to find two different equations that go through the point (2,5). Point slope form will make this relatively easy. $$y_2-y_1=m(x_2-x_1)$$ We must have (2,5) as the point. This means: $$y-5=m(x-2)$$ For m, we will pick two different real number values. This gives the two equations: $$y-5=2(x-2)$$ $$y-5=3(x-2)$$