Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.1 - Graphing Equations - Exercise Set - Page 127: 86

Answer

Please see the graph.

Work Step by Step

$y=x^2+2x+3$ Let $x=-3$ $y=x^2+2x+3$ $y=(-3)^2+2*(-3)+3$ $y=9-6+3$ $y=3+3$ $y=6$ Let $x=-2$ $y=x^2+2x+3$ $y=(-2)^2+2*(-2)+3$ $y=4-4+3$ $y=0+3$ $y=3$ Let $x=-1$ $y=x^2+2x+3$ $y=(-1)^2+2*(-1)+3$ $y=1-2+3$ $y=-1+3$ $y=2$ Let $x=0$ $y=x^2+2x+3$ $y=(0)^2+2*(0)+3$ $y=0+0+3$ $y=3$ Let $x=1$ $y=x^2+2x+3$ $y=(1)^2+2*(1)+3$ $y=1+2+3$ $y=3+3$ $y=6$ We have the ordered pairs $(-3,6), (-2,3), (-1,2), (0,3), (1,6)$
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