Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Review - Page 668: 66

Answer

$$1110 \ seats$$

Work Step by Step

We know the following series to represent the given situation: $$\sum _{i=2}^{20}\:\left(a_{i-1}+3\right)$$ Where $a_1$ is equal to 2, since this is the number of seats in the first row. Simplifying, we find the total number of rows is: $$1110 \ seats$$
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